先上代碼，nocodenosay/*classPoint{//...};*/Point*pPoint=newPoint;//1Pointpoint;//2*pPoint=point;//3//...deletepPoint//4關(guān)于步驟1new可分解為如下：//cpp為代碼Point*pPoint=__new(sizeof(Point));//5if(pPoint){pPoint->Point::Point();}步驟3，是不是就是調(diào)用Point的拷貝賦值函數(shù)？步驟4刪除該指針就是針對(duì)步驟5進(jìn)行分配的內(nèi)存進(jìn)行釋放？我這樣理解是否有錯(cuò)？