首先上數(shù)組
Array
(
[0] => Array
(
[tid] => 12
[aid] => 1
[openid] => oWWUP0dieOLSHl3CzjyHIcIsadhtVo
[nickname] => 帥鍋你好帥
[sales] =>
[team_name] => 帥
[team_slogan] => 酷
[title] => 測試活動
[new] => Array
(
[0] => Array
(
[id] => 1
[openid] => oWWUP0dieOLSHl3CzjyHIcIsadhtVo
[nickname] => 帥鍋你好帥
[tid] => 12
[cre_time] => 1512704950
[aid] => 0
[sales] => 12
)
[1] => Array
(
[id] => 3
[openid] => oWWUP0UXRfKKA6imX_X-6OU7OKv0
[nickname] => landy
[tid] => 12
[cre_time] => 1512704975
[aid] => 0
[sales] => 54
)
)
)
[1] => Array
(
[tid] => 13
[aid] => 2
[openid] => oWWUP0dieOLSHl3CzjyHIcIsadhtVo
[nickname] => 帥鍋你好帥
[sales] =>
[team_name] => 帥
[team_slogan] => 酷
[title] => 測按時
[new] => Array
(
[0] => Array
(
[id] => 2
[openid] => oWWUP0dieOLSHl3CzjyHIcIsadhtVo
[nickname] => 帥鍋你好帥
[tid] => 13
[cre_time] => 1512704970
[aid] => 2
[sales] => 24
)
)
)
)
我想計算
[0][new][sales]的總和
[1][new][sales]的總和
我不知道數(shù)組到底會有多大的....所以.....
我就知道我需要..new 下 tid 相同的話,sales 求和
求大家?guī)蛶兔Π?~~我菜鳥...
?!
3 回答
拉風的咖菲貓
TA貢獻1995條經(jīng)驗 獲得超2個贊
foreach ($data as $key => $value) {
$data[$key]['sum'] = array_sum(array_column($value['new'], 'sales'));
}
不知道是不是你要的結(jié)果，其實這種直接通過數(shù)據(jù)庫查詢更好計算吧
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