$arr = [
['num' => -1],
['num' => 1],
['num' => 2],
['num' => 3],
['num' => 8],
['num' => 9],
['num' => 10],
['num' => 11],
['num' => 20],
['num' => 21],
['num' => 22],
['num' => 25],
['num' => 30],
['num' => 31],
['num' => 32],
['num' => 100],
];
現(xiàn)在的要求是，如果數(shù)組中num值相減大于1的話，就給它分割成一個新的數(shù)組，處理成這樣：
$arr = [
[
['num' => -1],
],
[
['num' => 1],
['num' => 2],
['num' => 3],
],
[
['num' => 8],
['num' => 9],
['num' => 10],
['num' => 11],
],
[
['num' => 20],
['num' => 21],
['num' => 22],
],
[
['num' => 25]
],
[
['num' => 30],
['num' => 31],
['num' => 32],
],
[
['num' => 100],
]
];
想請教下，用PHP該怎么處理？
1 回答
慕桂英3389331
TA貢獻2036條經(jīng)驗 獲得超8個贊
至少for循環(huán)還是能想到..
function continuous($arr, $field = "num")
{
$result = [];
$temp = [
$arr[0],
];
for ($i = 1; $i < count($arr); $i++) {
$prev = $arr[$i - 1][$field];
$now = $arr[$i][$field];
if ($now - $prev == 1) {
$temp[] = $arr[$i];
} else {
if ($temp) {
$result[] = $temp;
}
$temp = [$arr[$i]];
}
}
if(!empty($temp)) {
$result[] = $temp;
}
return $result;
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