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php計(jì)算一月中有多少個(gè)周末

php計(jì)算一月中有多少個(gè)周末

PHP
陪伴而非守候 2019-03-18 15:31:26
找到的一個(gè)方案如下: function get_weekend_days($start_date, $end_date, $weekend_days=1) { $data = array(); $start_reduce = $end_add = 0; $start_N = date('N',strtotime($start_date)); $start_reduce = ($start_N == 7) ? 1 : 0; $end_N = date('N',strtotime($end_date)); // 進(jìn)行單、雙休判斷,默認(rèn)按單休計(jì)算 $weekend_days = intval($weekend_days); switch ($weekend_days) { case 2: in_array($end_N,array(6,7)) && $end_add = ($end_N == 7) ? 2 : 1; break; case 1: default: $end_add = ($end_N == 7) ? 1 : 0; break; } $days = ((strtotime($end_date) - strtotime($start_date))/86400) + 1; $data['total_days'] = $days; $data['total_relax'] = floor(($days + $start_N - 1 - $end_N) / 7) * $weekend_days - $start_reduce + $end_add; return $data; } 這個(gè)$data['total_relax'] 為什么要這樣計(jì)算呢? 這方法好像不太好用,比如今天 是周天 但是返回的$data['total_relax']是0
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1 回答

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慕田峪9158850

TA貢獻(xiàn)1794條經(jīng)驗(yàn) 獲得超7個(gè)贊

試試這個(gè)修改過(guò)的

<?php

function get_weekend_days($start_date, $end_date, $weekend_days=1) {

$data = array();

$start_reduce = $end_add = 0;
$start_N      = date('N',strtotime($start_date));


$end_N = date('N',strtotime($end_date));

// 進(jìn)行單、雙休判斷,默認(rèn)按單休計(jì)算
$weekend_days = intval($weekend_days);
switch ($weekend_days)
{
    case 2:
        in_array($end_N,array(6,7)) && $end_add = ($end_N == 7) ? 2 : 1;
        $start_reduce = ($start_N == 7) ? 1 : 0;
        break;
    case 1:
    default:
        $end_add = ($end_N == 7) ? 1 : 0;
        break;
}

$days = ((strtotime($end_date) - strtotime($start_date))/86400) + 1;
$data['total_days'] = $days;
$data['total_relax'] = floor(($days + $start_N - 1 - $end_N) / 7) * $weekend_days - $start_reduce + $end_add;

return $data;
}

echo "Two days per week\n";
var_dump( get_weekend_days("2018-03-31","2018-04-08",2));
var_dump( get_weekend_days("2018-04-01","2018-04-08",2));
var_dump( get_weekend_days("2018-04-02","2018-04-08",2));
var_dump( get_weekend_days("2018-04-07","2018-04-08",2));
var_dump( get_weekend_days("2018-04-08","2018-04-08",2));
echo "One day per week\n";
var_dump( get_weekend_days("2018-03-31","2018-04-08",1));
var_dump( get_weekend_days("2018-04-01","2018-04-08",1));
var_dump( get_weekend_days("2018-04-02","2018-04-08",1));
var_dump( get_weekend_days("2018-04-07","2018-04-08",1));
var_dump( get_weekend_days("2018-04-08","2018-04-08",1));
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反對(duì) 回復(fù) 2019-03-18
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