如何對(duì)Scala中集合進(jìn)行排序
如何對(duì)Scala中集合進(jìn)行排序
慕斯王
2019-03-05 05:04:48
3 回答
翻翻過(guò)去那場(chǎng)雪
TA貢獻(xiàn)2065條經(jīng)驗(yàn) 獲得超14個(gè)贊
如何對(duì)Map中的Key或Value進(jìn)行排序
其實(shí)很簡(jiǎn)單代碼如下：
// sort by key can use sorted
m.toList.sorted foreach {
case (key,value) =>
println(key + " = " + value)
}
-2 = 5
-1 = -4
0 = -16
1 = 2
2 = 6
5 = 9
// sort by value
m.toList sortBy ( _._2 ) foreach {
case (key,value) =>
println(key + " = " + value)
}
0 = -16
-1 = -4
1 = 2
-2 = 5
2 = 6
5 = 9
智慧大石
TA貢獻(xiàn)1946條經(jīng)驗(yàn) 獲得超3個(gè)贊
val list1 = List(1, 2, 3, 4, 5, 6)
list1.sorted
list1.sortWith(_ > _)
val sortedSet = scala.collection.immutable.SortedSet(2, 3, 4, 5, 1)
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