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JS如何判斷input中密碼輸入的數(shù)字是否為連續(xù)數(shù)字?

JS如何判斷input中密碼輸入的數(shù)字是否為連續(xù)數(shù)字?

6位支付密碼設(shè)置,如何判斷input中輸入的數(shù)字是否為連續(xù)數(shù)字?如果是則提醒用戶安全較低。例如:333333,這是6位的相同的123456或234567或987654,這種連續(xù)的使用JS的.test()來(lái)判斷,正則應(yīng)該怎么寫?
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12345678_0001

TA貢獻(xiàn)1802條經(jīng)驗(yàn) 獲得超5個(gè)贊

沒有想到正則的方法,自己寫了一個(gè)函數(shù):

檢測(cè)序列是0123456789:


function isContinue(str) {

  let diff = +str[1] - +str[0]

  diff = diff < 0 ? diff + 10 : diff

  let former = +str[0]


  for (let i = 1; i < str.length; i++) {

    let cur0 = +str[i]

    let cur1 = former + diff

    cur1 = cur1 < 0 ? cur1 + 10 : cur1 % 10

    if (cur0 !== cur1) return false

    former = cur0

  }

  return true

}

console.log(isContinue('987654')) // true

console.log(isContinue('432109')) // true

console.log(isContinue('123456')) // true

console.log(isContinue('901234')) // true

console.log(isContinue('201235')) // false

檢測(cè)的序列是123456789:


function isContinue(str) {

  let base = 9

  let strArray = []

  for (let i = 0, len = str.length; i < len; i++) {

    let j = +str[i] - 1

    strArray[i] = j < 0 ? j + base : j

  }

  str = strArray.join('')


  let diff = +str[1] - +str[0]

  diff = diff < 0 ? diff + base : diff

  let former = +str[0]


  for (let i = 1; i < str.length; i++) {

    let cur0 = +str[i]

    let cur1 = former + diff

    cur1 = cur1 < 0 ? cur1 + base : cur1 % base

    if (cur0 !== cur1) return false

    former = cur0

  }

  return true

}

console.log(isContinue('987654')) // true

console.log(isContinue('432198')) // true

console.log(isContinue('123456')) // true

console.log(isContinue('912345')) // true

console.log(isContinue('901234')) // false


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?
弒天下

TA貢獻(xiàn)1818條經(jīng)驗(yàn) 獲得超8個(gè)贊

function fun(str) {

    if (str.length < 2)

        return false;

    var t = str.charCodeAt(0) - str.charCodeAt(1);

    for (var i = 0,l=str.length; i < l - 1; i++)

        if ((str.charCodeAt(i) - str.charCodeAt(i + 1)) != t)

            return false;

    return true;

}

fun('123456')

正則的話太麻煩了


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