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一個數組里有多個對象，如何根據對象某個相同屬性，重新組成新數組，如下圖和代碼

Python

慕虎7371278 2019-02-21 19:30:36

問題如下data數組，如何根據相同的 "shop_id" "shop_name" 轉成data1數組 data var data = [{ "cart_goods_number": 3, "goods_id": 3, "goods_name": "honor7x", "goods_img": "honor7x.png", "goods_price": 1299, "shop_id": 4, "shop_name": "honor之家" }, { "cart_goods_number": 2, "goods_id": 4, "goods_name": "honor6x", "goods_img": "honor6x.png", "goods_price": 1199, "shop_id": 4, "shop_name": "honor之家" }, { "cart_goods_number": 1, "goods_id": 1, "goods_name": "iPhonex", "goods_img": "iPhonex.png", "goods_price": 8888, "shop_id": 1, "shop_name": "iPhone之家" }] data1 var data1 = [{ "shop_id": 4, "shop_name": "honor之家", goodsList: [{ "cart_goods_number": 3, "goods_id": 3, "goods_name": "honor7x", "goods_img": "honor7x.png", "goods_price": 1299, }, { "cart_goods_number": 2, "goods_id": 4, "goods_name": "honor6x", "goods_img": "honor6x.png", "goods_price": 1199, }] }, { "shop_id": 1, "shop_name": "iPhone之家", goodsList: [{ "cart_goods_number": 1, "goods_id": 1, "goods_name": "iPhonex", "goods_img": "iPhonex.png", "goods_price": 8888, }] }]

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7 回答

翻翻過去那場雪

TA貢獻2065條經驗獲得超14個贊

    var newData = [];
    data.forEach(function(item) {
        for (var i = 0; i < newData.length; i++) {
            if (newData[i].shop_id === item.shop_id) {
                newData[i].goodsList.push({
                    goods_id: item.goods_id,
                    goods_name: item.goods_name,
                    goods_img: item.goods_img,
                    goods_price: item.goods_price
                })

                return;
            }
        }
        newData.push({
            shop_id: item.shop_id,
            shop_name: item.shop_name,

            goodsList: [{
                goods_id: item.goods_id,
                goods_name: item.goods_name,
                goods_img: item.goods_img,
                goods_price: item.goods_price
            }]
        })
    })
    console.log(newData)

1 反對回復 2019-03-01

寶慕林4294392

TA貢獻2021條經驗獲得超8個贊

function func (data) {
  const newData = []
  data.forEach(item => {
    const indexFound = newData.findIndex(newItem => newItem.shop_id === item.shop_id)
    const currentGoods = {
      cart_goods_number: item.cart_goods_number,
      goods_name: item.goods_name,
      goods_img: item.goods_img,
      goods_price: item.goods_price,
      goods_id: item.goods_id
    }
    if (indexFound > -1) {
      newData[indexFound].goodsList.push(currentGoods)
    } else {
      newData.push({
        shop_id: item.shop_id,
        shop_name: item.shop_name,
        goodsList: [currentGoods]
      })
    }
  })
  return newData
}

反對回復 2019-03-01

哈士奇WWW

TA貢獻1799條經驗獲得超6個贊

function trans (data, keys) {
    let cache = {}
    return data.reduce((sum, cur) => {
        let obj = {}
        let key = keys.reduce((sum, key) => {
            let tmp = obj[key] = cur[key]
            delete cur[key]
            return sum + tmp
        }, '')

        let i = cache[key]
        if (i !== undefined) {
            sum[i].goodsList.push(cur)
        } else {
            cache[key] = sum.length
            sum.push(Object.assign(obj, {goodsList: [cur]}))
        }
        return sum
    }, [])
}
trans(data, ['shop_id', 'shop_name'])

反對回復 2019-03-01

犯罪嫌疑人X

TA貢獻2080條經驗獲得超4個贊

let result = data.reduce((result, item) => {
    let index = result.findIndex(v => v.shop_id === item.shop_id);
    let {shop_id,shop_name,...single} = item;
    if (index === -1) {
        result.push({shop_id,shop_name,goods_list:[single]});
    } else {
        result[index].goods_list.push(single);
    }
    return result;
}, []);
console.log(result);

反對回復 2019-03-01

互換的青春

TA貢獻1797條經驗獲得超6個贊

把這個問題向前占個位置，我想知道這個問題的 Python 解決方法。

反對回復 2019-03-01

LEATH

TA貢獻1936條經驗獲得超7個贊

import collections
import json
result = collections.defaultdict(list)
for item in data:
  temp = dict(
    shop_id=item.pop('shop_id'),
    shop_name=item.pop('shop_name')
  )
  result[json.dumps(temp)].append(item)
result_new = list()
for k, v in result.items():
  temp = dict()
  temp.update(json.loads(k))
  temp['goodsList'] = v
  result_new.append(temp)

assert cmp(result_new, data1) == 0

反對回復 2019-03-01

嗶嗶one

TA貢獻1854條經驗獲得超8個贊

def test(args, args1, args2, args3):
    data1, data3, b = list(), list(), 0
    for i in args:
        j = i.copy()
        j.pop(args1)
        j.pop(args2)
        a = "{}{}".format(i.get(args1), i.get(args2))
        if a not in data3:
            data1.append({args1: i.get(args1), args2: i.get(args2), args3: [j]})
            data3.append(a)
            b = data3.index(a)
        else:
            data1[b][args3].append(j)
    return data1


print test(data, "shop_id", "shop_name", "goodsList")

反對回復 2019-03-01