在main函數(shù)里面調(diào)用了join,查看了join的源碼,調(diào)用join會(huì)轉(zhuǎn)換為調(diào)用wait(0),比如下面的代碼
public static void main(String[] args) {
Thread r1 = new Thread(new X("r1"))
r1.start();
try {
r1.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Main finished");
}
但是,一般說(shuō)A調(diào)用了wait則需要使用notify或者notifyAll喚醒線程A,而在join的代碼當(dāng)中并沒(méi)有看到這兩個(gè)函數(shù)對(duì)main線程的notify,那么main是怎么從join里面的wait(0)出來(lái)再進(jìn)行循環(huán)判斷的?(下面是join的源碼,調(diào)用join(),在join()內(nèi)部會(huì)直接調(diào)用join(0),也就是下面這個(gè)函數(shù))
public final synchronized void join(long millis)
throws InterruptedException {
long base = System.currentTimeMillis();
long now = 0;
if (millis < 0) {
throw new IllegalArgumentException("timeout value is negative");
}
if (millis == 0) {
while (isAlive()) {
wait(0);
}
} else {
while (isAlive()) {
long delay = millis - now;
if (delay <= 0) {
break;
}
wait(delay);
now = System.currentTimeMillis() - base;
}
}
}
1 回答

慕勒3428872
TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超6個(gè)贊
Thread執(zhí)行完成后 會(huì)自動(dòng)實(shí)現(xiàn)notifyAll功能,這個(gè)屬于jvm c++層面的東西,所以java代碼中是不需要顯示的notify的
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