publicclass Test1
?
??? {
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??????? private int _age=10;
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??????? public int Age
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??????? {
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??????????? get { return _age; }
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??????????? set { _age = value; }
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??????? }
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??????? public virtual void? Output1(string name)
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??????? {
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??????????? name ="Test1";
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???? ???????Console.Write("Test1.Output1 ：Name is "+ name);
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??????? }
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??????? public virtual void Output2(ref stringrefname)
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??????? {
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??????????? refname = "Test1";
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? ??????????Console.Write("Test1.Output2 ：Name is " + refname);
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??????? }
?
??? }
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??? public class Test2:Test1
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??? {
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??????? private int _age=20;
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??????? public override void Output1(stringname)
?
??????? {
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??????????? name ="Test2";
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??????????? Console.Write("Test2.Output1 ：Name is "+ name);
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??????? }
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??????? public new void Output2(ref stringrefname)
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??????? {
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??????????? refname = "Test2";
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??????????? Console.Write("Test2.Output2 ：Name is " + refname);
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??????? }
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??????? }
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??????? string name = "Name";
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??????? string refname = "RefName";
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??????? Test1 t1 = new Test2();
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??????? t1.Output1(name);? //輸出1？
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??????? t1.Output2(ref refname);? // 輸出2？
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??????? Console.Write(name); // 輸出3？
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??????? Console.Write(refname); // 輸出4？
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??????? Test2 t2 = new Test2();
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??????? Console.Write(t2.Age.ToString()); //輸出5以及是否裝箱？
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??????? t2.Output2(ref refname);? //輸出6
1 回答
慕姐8265434
TA貢獻(xiàn)1813條經(jīng)驗(yàn) 獲得超2個贊
Test2類重寫了Test1類的OutPut1方法，隱藏了OutPut2方法，因此t1.OutPut1(name)輸出應(yīng)該調(diào)用的是重寫后的方法即t2中的方法，輸出應(yīng)為：est2.Output1 ：Name is Test2；t1.OutPut2(ref refname)輸出應(yīng)該是：Test1.Output2 ：Name is ?Test1。Console.Write(name)輸出為：Name;Console.Write(refName）應(yīng)為Test2。Console.Write(t2.Age.ToString())不是很清楚。t2.Output2(ref refname)輸出：Test2.Output2 ：Name is ?test2
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