public static int[] DataDifference(int[] more, int[] few)
{
//差異Id
var sbuNoItapSessionId = new int[more.Length - few.Length];
var indexi = 0;
for (int i = 0; i < more.Length; i++)
{
var isHave = false;
for (int j = 0; j < few.Length; j++)
{
if (more[i].Equals(few[j]))
{
isHave = true;
break;
}
}
if (!isHave)
{
sbuNoItapSessionId[indexi] = more[i];
indexi++;
}
}
return sbuNoItapSessionId;
}
public static string[] DataDifference(string[] more, string[] few)
{
//差異Id
var sbuNoItapSessionId = new string[more.Length - few.Length];
var indexi = 0;
for (int i = 0; i < more.Length; i++)
{
var isHave = false;
for (int j = 0; j < few.Length; j++)
{
if (more[i].Equals(few[j]))
{
isHave = true;
break;
}
}
if (!isHave)
{
sbuNoItapSessionId[indexi] = more[i];
indexi++;
}
}
return sbuNoItapSessionId;
}
public static ResultMessage StitchingAndReturnsAnArray(int[] datas)
{
var noIds = new StringBuilder();
var result = new ResultMessage();
if (datas != null && datas.Count() != 0)
{
for (int i = 0; i < datas.Length; i++)
{
if (i > 0)
{
noIds.Append(",");
}
noIds.Append(datas[i]);
}
result.Success = "false";
result.Message = noIds.ToString();
}
else
{
result.Success = "true";
}
return result;
}
public static ResultMessage StitchingAndReturnsAnArray2(string[] datas)
{
var noIds = new StringBuilder();
var result = new ResultMessage();
if (datas != null && datas.Count() != 0)
{
for (int i = 0; i < datas.Length; i++)
{
if (i > 0)
{
noIds.Append(",");
}
noIds.Append(datas[i]);
}
result.Success = "false";
result.Message = noIds.ToString();
}
else
{
result.Success = "true";
}
return result;
}
?
可以看到代碼中代碼基本全部都重復(fù)，可是像這樣只是類型不同的方法，又該怎么去優(yōu)化呢？
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