首頁猿問 Json數(shù)據(jù)怎么去掉重復(fù)的數(shù)據(jù)

Json數(shù)據(jù)怎么去掉重復(fù)的數(shù)據(jù)

JavaScript

jeck貓 2018-12-07 05:40:19

[{Title:"中交大酒店",Address:"柳州解放北路1號(hào)",Content:"undefined",Points:"109.419662 |24.322459",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}, {Title:"柳州市藝術(shù)賓館",Address:"柳州市八一路8號(hào)",Content:"undefined",Points:"109.415949|24.325656",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}, {Title:"柳州市藝術(shù)賓館",Address:"柳州市八一路8號(hào)",Content:"undefined",Points:"109.415949|24.325656",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}, {Title:"柳安大廈賓館",Address:"柳州市文筆路91號(hào)",Content:"undefined",Points:"109.417615|24.317366",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}] 把上面重復(fù)的【柳州市藝術(shù)賓館】去掉，留一個(gè) [{Title:"中交大酒店",Address:"柳州解放北路1號(hào)",Content:"undefined",Points:"109.419662 |24.322459",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}, {Title:"柳州市藝術(shù)賓館",Address:"柳州市八一路8號(hào)",Content:"undefined",Points:"109.415949|24.325656",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}, {Title:"柳安大廈賓館",Address:"柳州市文筆路91號(hào)",Content:"undefined",Points:"109.417615|24.317366",IsOpen:0,Icon:{w:21,h:21,l:0,t:0,x:6,lb:5}}]

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4 回答

侃侃無極

TA貢獻(xiàn)2051條經(jīng)驗(yàn) 獲得超10個(gè)贊

我想到的方法是先轉(zhuǎn)換為對(duì)象，然后再處理重復(fù)數(shù)據(jù)。

反對(duì) 回復(fù) 2018-12-24

慕無忌1623718

TA貢獻(xiàn)1744條經(jīng)驗(yàn) 獲得超4個(gè)贊

數(shù)據(jù)庫中有重復(fù)數(shù)據(jù)，建議都不要把重復(fù)數(shù)據(jù)查出來,呵呵，要不然就只能，樓上所說的，轉(zhuǎn)成對(duì)象，才可以去重復(fù)了

反對(duì) 回復(fù) 2018-12-24

波斯汪

TA貢獻(xiàn)1811條經(jīng)驗(yàn) 獲得超4個(gè)贊

能添個(gè)代碼么。我是菜鳥要看代碼才能解決啊

反對(duì) 回復(fù) 2018-12-24

胡子哥哥

TA貢獻(xiàn)1825條經(jīng)驗(yàn) 獲得超6個(gè)贊

//JOSN數(shù)組去重的算法 JS
Array.prototype.unique1 = function () {
var res = [this[0]];
for (var i = 1; i < this.length; i++) {
var repeat = false;
for (var j = 0; j < res.length; j++) {
if (this[i]== res[j]) {
repeat = true;
break;
}
}
if (!repeat) {
res.push(this[i]);
}
}
return res;
}