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java 中 Method.invoke()問題

Java

瀟瀟雨雨 2018-12-06 16:36:04

當(dāng)我獲取某一個類中的所有方法時，然后遍歷數(shù)組(Method[] methods)，每一個方法的參數(shù)類型都不相同，想動態(tài)賦值如:Method.invoke(XXX,100); Method.invoke(XXX, "yyyy");

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package cnblogs;

import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;
import java.lang.reflect.Type;

/**
 * Created by Kischn on 2015/11/25.
 */
public class ReflectTest {
    public static void main(String[] args) {
        Class<ReflectTest> t = ReflectTest.class;
        Method[] declaredMethods = t.getMethods();
            for(Method method : declaredMethods) {
                System.out.print(method.getReturnType());
                System.out.print(' ');
                System.out.println(method.getName());
                System.out.println("params:");
                Type[] genericParameterTypes = method.getGenericParameterTypes();
                for (Type type : genericParameterTypes) {
                    System.out.println(type.getTypeName());
                }
                System.out.println("---------------");
            }
    }

    public void sayHello(String name){
        System.out.print("hello" + name);
    }
}

void main
params:
java.lang.String[]
---------------
void sayHello
params:
java.lang.String
---------------
void wait
params:
---------------
void wait
params:
long
int
---------------
void wait
params:
long
---------------
boolean equals
params:
java.lang.Object
---------------
class java.lang.String toString
params:
---------------
int hashCode
params:
---------------
class java.lang.Class getClass
params:
---------------
void notify
params:
---------------
void notifyAll
params:
---------------