用運算符號使下面等式成立，不添加額外數(shù)字1 1 1 = 62 + 2 + 2 = 63 3 3 = 64 4 4 = 65 5 5 = 66 6 6 = 67 7 7 = 68 8 8 = 69 9 9 = 6
2 回答
楊魅力
TA貢獻1811條經(jīng)驗 獲得超6個贊
let a = [2,2,2,2,2,2,2,2,2,2];
a[1] + a[1] + a[1] = 6
2 + 2 + 2 = 6
a[3] + a[3] + a[3] = 6
a[4] + a[4] + a[4] = 6
a[5] + a[5] + a[5] = 6
a[6] + a[6] + a[6] = 6
a[7] + a[7] + a[7] = 6
a[8] + a[8] + a[8] = 6
a[9] + a[9] + a[9] = 6
MM們
TA貢獻1886條經(jīng)驗 獲得超2個贊
( 1 + 1 + 1 )! = 6
2 + 2 + 2 = 6
3 * 3 - 3 = 6
4 + 4 - sqrt(4) = 6
5 + 5 / 5 = 6
6 * 6 / 6 = 6
7 - 7 / 7 = 6
8 - sqrt( sqrt( 8 + 8 )) = 6
9 - 9 / sqrt(9) = 6
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