Passwrong << < 1, 1 >> >(cuda_dcA, cuda_dcAa, a, cuda_factAnum);
global
void Passwrong(int *a, int*b,int num,int*TN)
{int countA = 0;
for (int ia = 0; ia < num; ia++)
{
if (a[ia * 5] == 1 && a[ia * 5 + 1] == 1 && a[ia * 5 + 2] == 1 && a[ia * 5 + 3] == 1 && a[ia * 5 + 4] == 1)
{
continue;
}
else
{
for (int ja = 0; ja < 5; ja++)
{
b[countA * 5 + ja] = a[ia * 5 + ja];
}
countA++;
}
}
TN[0] = countA;
}這種寫法會爆炸，不明原因。。。。
在cuda中如何挑選gpu數(shù)組中滿足特定條件的數(shù)據(jù),并組成一個新的數(shù)組(不要把值賦給cpu計(jì)算)
嚕嚕噠
2018-07-16 14:22:47