我的Controller其中一個(gè)方法如下,入?yún)⒅皇荂ommonsMultipartFile 類型,請(qǐng)問在單元測(cè)試中如何構(gòu)造CommonsMultipartFile 實(shí)例進(jìn)行單元測(cè)試@ModelAttributepublic PicUpload get(@RequestParam(required = false) String id,@RequestParam(required = false) CommonsMultipartFile picupload) {PicUpload entity = null;if (StringUtils.isNotBlank(id)) {entity = picUploadService.get(id);}if (entity == null) {entity = new PicUpload();}return entity;}
關(guān)于如何構(gòu)造CommonsMultipartFile 類型的單元?
慕工程0101907
2018-07-11 10:12:46