def?f1(x):
????return?x*2
def?new_fn(f):
????def?fn(x):
????????print?'call'?+?f.__name__?+?'()'
????????return?f(x)???#這里最不懂,哪來的f()?
????return?fn
g1?=?new_fn(f1)
print?g1(5)
能解釋一下這段代碼嗎?
錯(cuò)過了年華
2017-12-28 20:35:30