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ajax怎么不能賦值到前臺?

ajax怎么不能賦值到前臺?

錯過了年華 2017-10-27 03:32:58
?<div?class="pay"> ????????????????<div?class="pay-opt">?<a?href="home2.html"><span?class="am-icon-home?am-icon-fw">首頁</span></a>?<a><span?class="am-icon-heart?am-icon-fw">收藏</span></a>?</div> ????????????????<li> ????????????????????<div?class="clearfix?tb-btn?tb-btn-buy?theme-login">?<a?id="LikBuy"?title="點此按鈕到下一步確認購買信息"?href="#">立即購買</a>?</div> ????????????????</li> ????????????????<li> ????????????????????<div?class="clearfix?tb-btn?tb-btn-basket?theme-login">?<a?id="LikBasket"?title="加入購物車"?href="javascript:addCart({$rst[0]['g_id']})"?onClick="showSum()"><i></i>加入購物車</a>?</div> ????????????????</li> ????????????</div> ????????</div> ????????<div?class="clear"></div> ????</div> ???{literal}?<script?type="text/javascript"> ????????? ??????????function?showSum(){ ??????????????var?url?=?"countShopcartid.php"; ?????????????? ?????????????? ?????????????var?data?=?{"not":""}; ??????????????var?success=?function(response){ ??????????????????if(response.errno?==?0){ ????????????????????var?sum?=?response.sum;?? ??????????????????$("#LikBuy").html("sum"); ??????????????????}else ??????????????????{ ???????????????????????alert('獲取購物車商品數(shù)量失敗'); ??????????????????} ??????????????} ??????????????$.post(url,data,success,"json"); ??????????} ????</script>{/literal}countShopcartid.php <?php require_once('include.php'); //1.接受參數(shù)并處理 $user_id?=?$_SESSION["id"]; //2.計算數(shù)量 $sql?=?"select?count(*)?from?shopcar?where??user_id='{$user_id}'"; $row?=?$admindb->ExecSQL($sql,$conn); var_dump($row); //3.返回處理結(jié)果 if($row){ $response?=?array( 'errno'?=>0, 'errmsg'?=>'success', 'data'?=>?true, 'sum'?=>?$row[0]["count(*)"], ); } else{ $response?=?array( 'errno'?=>-1, 'errmsg'?=>'fail', 'data'?=>?false, 'sum'?=>?$row[0]["count(*)"], ); } echo?json_encode($response); ?>F12看到有值????? {"errno":0,"errmsg":"success","data":true,"sum":"4"}?? 為什么sum沒賦值到? #LikBuy的a標簽里,還是我哪里寫錯了?
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$("#LikBuy").html("sum");
這里改成
$("#LikBuy").html(sum);
看到了嗎?

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