for (int i = 0; i < a.length; i++) {?????System.out.println("輸入你要增加學(xué)員的學(xué)號(hào):");?????int xh = input.nextInt();?????boolean f = false;?????if (xh > 000 && xh < 100) {??????for (int j = 0; j < a.length; j++) {???????if (xh!=a[i].getId()) {????????f = true;????????System.out.println("hah ");????????break;???????}??????}??????if (f = true) {???????a[i].setId(xh);???????System.out.println("恭喜你,學(xué)員學(xué)號(hào)錄入成功");???????break;??????} else {???????a[i].setId(xh);???????System.out.println("抱歉,學(xué)號(hào)已存在");???????break;??????}?????} else {??????System.out.println("學(xué)號(hào)是這樣滴?");?????}????}
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有好幾處邏輯錯(cuò)誤，第一段：
boolean f = false;
???? if (xh > 000 && xh < 100) {
????? for (int j = 0; j < a.length; j++) {
?????? if (xh!=a[i].getId()) {
??????? f = true;
??????? System.out.println("hah ");
??????? break;
?????? }
????? }
這里你的本意是判斷是否有重復(fù)對(duì)吧？那應(yīng)該是這樣的：
boolean f = false;
???? if (xh > 000 && xh < 100) {
????? for (int j = 0; j < a.length; j++) {
?????? if (xh==a[i].getId()) {? //這里，只有相等了才會(huì)標(biāo)記為true。
??????? f = true;
??????? System.out.println("Exist! ");
??????? break;
?????? }
????? }
第二個(gè)錯(cuò)誤：
if(f=true)
應(yīng)該為：
if(f)? 或者寫(xiě)作? if(f==true)
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