首頁猿問集合排序功能

集合排序功能

Java

折_柳 2017-08-24 19:13:41

定義一副紙牌，有發(fā)牌功能，3個人在玩，每個人10張，然后按花色排序看牌再按點數(shù)排序看牌應(yīng)該怎樣去做，3個人分別為張三，李四，王五

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1 回答

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import?java.util.ArrayList;
import?java.util.Collections;
import?java.util.Iterator;
import?java.util.List;

public?class?Main?{
????public?static?Card?getBiggest(List<Card>?card){//得到最大的那張牌。
????????if(card==null)return??null;
?????????Iterator<Card>iterator=card.iterator();//用Iterator遍歷集合
?????????Card?temp=new?Card(Card.Points._3,?Card.Colour.黑桃?);//temp初始值為最小的牌
?????????while?(iterator.hasNext()){
?????????????Card?c=iterator.next();
?????????????if(c.compareTo(temp)>0){
?????????????????temp=c;
?????????????}
?????????}
?????????return?temp;
????}
????public?static?void?main(String[]?args)?{
????????/*
????????*
????????*?創(chuàng)建有序牌堆
????????*/
????????List<Card>?card=new?ArrayList<Card>();//創(chuàng)建空牌堆
????????for(Card.Points?p:Card.Points.values()){
????????????for?(Card.Colour?c:?Card.Colour.values()){
????????????????card.add(new?Card(p,c));
????????????}
????????}
//????????for(Card?c:card){
//????????????System.out.println(c.toString());
//????????}
????????/*
????????*?洗牌
????????*?shuffle（）方法
????????*
????????*?*/
????????Collections.shuffle(card);
????????/*
????????*?發(fā)牌
????????*
????????*?*/
????????List<Card>?player1=new?ArrayList<Card>();
????????List<Card>?player2=new?ArrayList<Card>();
????????List<Card>?player3=new?ArrayList<Card>();
????????int?newPosition=1;
????????for?(Card?c:card
?????????????)?{
????????????if(newPosition%3==0)player3.add(c);
????????????if(newPosition%3==1)player1.add(c);
????????????if(newPosition%3==2)player2.add(c);
????????????if(newPosition>=9)break;//修改參數(shù)可以改變剩余牌數(shù)
????????????newPosition++;
????????}
//????????for(Card?c:player1){
//????????????System.out.println(c.toString());
//????????}

????????Card?p1=getBiggest(player1);
????????Card?p2=getBiggest(player2);
????????Card?p3=getBiggest(player3);
????????if(p1.compareTo(p2)>0&&p1.compareTo(p3)>0){
????????????System.out.println("player1?has?the?biggest?card:"+p1.toString());
????????}else??if(p2.compareTo(p1)>0&&p2.compareTo(p3)>0){
????????????System.out.println("player2?has?the?biggest?card:"+p2.toString());
????????}else?{
????????????System.out.println("player3?has?the?biggest?card:"+p3.toString());
????????}
????}

}

基本功能是實現(xiàn)了，看看對你有沒有用。

1 反對回復(fù) 2017-08-24