#include"stdio.h"#include"string.h"#include"conio.h"#include"windows.h"#include"math.h"int f ( int );int sum ( int );int main(){?int a,b;?printf("輸入一個整數(shù):");scanf("%d",&a);?b = sum ( a );?printf(" a = %d \t b = %d \n",a,b);?return 0;}int sum ( int n ){?int x;?int s = 0;?for ( x = 0; x <= n; x ++ )?{??s += f ( x );?}?return s;}int f ( int z ){?return z*z+1;}請講解一下答案是怎么算出來的?
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qq_企鵝_13輸入 a = 3; 得出 b = 18; 每一步是怎么循環(huán)的? 能把過程寫下來嗎? -
產(chǎn)品經(jīng)理不是經(jīng)理a=3; 循環(huán)的n=3; 每次循環(huán)調(diào)用f函數(shù)，f(1)=1*1+1=1,f(1)=1*1+1=2 f(2)=2*2+1=5,f(3)=3*3+1=10, 所以s=1+2+5+10=18
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