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python里的list求平均值

Python

Leo_clip 2017-06-19 23:34:21

def?pingjun(L=[]): a=reduce(lambda?x,y:x+y,L) return?a*1.0/len(L) L=[] for?i?in?range(0,10): num=input('enter?your?score:') L.append(int(num)) L.remove(max(L)) L.remove(min(L)) print(pingjun(L))這個(gè)函數(shù)并不能去掉最大值，而且求平均值的函數(shù)會(huì)報(bào)錯(cuò)，求解

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5 回答

已采納

產(chǎn)品經(jīng)理不是經(jīng)理

TA貢獻(xiàn)481條經(jīng)驗(yàn) 獲得超143個(gè)贊

python3里reduce不在內(nèi)建函數(shù)里面，需要from functools import reduce

1 反對(duì) 回復(fù) 2017-06-19

劉小米92

TA貢獻(xiàn)8條經(jīng)驗(yàn) 獲得超14個(gè)贊

#最大數(shù)
def?Get_Max(list):
???return?max(list)
#最小數(shù)
def?Get_Min(list):
???return?min(list)
#極差
def?Get_Range(list):
???return?max(list)?-?min(list)
???
#中位數(shù)
def?get_median(data):
???data?=?sorted(data)size?=?len(data)
???if?size?%?2?==?0:?
??????#?判斷列表長(zhǎng)度為偶數(shù)
??????median?=?(data[size//2]+data[size//2-1])/2
???if?size?%?2?==?1:?
??????#?判斷列表長(zhǎng)度為奇數(shù)
??????median?=?data[(size-1)//2]
???return?median

#眾數(shù)(返回多個(gè)眾數(shù)的平均值)
def?Get_Most(list):
???most=[]
???item_num?=?dict((item,?list.count(item))?
???for?item?in?list)for?k,v?in?item_num.items():
??????if?v?==?max(item_num.values()):
?????????most.append(k)
???return?sum(most)/len(most)
?????????
#獲取平均數(shù)
def?Get_Average(list):	
???sum?=?0	
???for?item?in?list:		
??????sum?+=?item	
???return?sum/len(list)

2 反對(duì) 回復(fù) 2018-01-25