long long ann1(long long n);long long john1(long long n);long long sumAnn(long long n);long long sumJohn(long long n);long long* ann(long long n);long long* john(long long n);long long* ann(long long n){? ? int i;? ? long long* a=(long long*)malloc(n*sizeof(long long));? ? for(i=0;i<n;i++)? ? ? ? a[i]=ann1(i);? ? return a;}long long* john(long long n){? ? int i;? ? long long* j=(long long*)malloc(n*sizeof(long long));? ? for(i=0;i<n;i++)? ? ? ? j[i]=john1(i);? ? return j;}long long sumJohn(long long n){? ? int i;? ? long long sum=0;? ? for(i=0;i<n;i++) ?? ? ? ? sum=sum+john1(i);? ? return sum;}long long sumAnn(long long n){? ? int i;? ? long long sum=0;? ? for(i=0;i<n;i++)? ? ? ? sum=sum+ann1(i);? ? return sum;}long long john1(long long n){? ? long long j;? ? if(n==0)? ? {? ? ? ? j=0;? ? ? ? return j;? ? }? ? j=n-ann1(john1(n-1));? ? return j;}long long ann1(long long n){? ? long long a;? ? if(n==0)? ? {? ? ? ? a=1;? ? ? ? return a;? ? }? ? a=n-john1(ann1(n-1));? ? return a;}
這段怎么簡(jiǎn)化啊(不用c++),求高手指點(diǎn)啊!!!!!!!!,在線等,急急急
給自己一個(gè)理由_
2016-12-09 15:57:30