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TA貢獻(xiàn)1017條經(jīng)驗 獲得超1032個贊
#include<stdio.h> void?main() { int?i,n; for(i=0;i<5;i++) { scanf("%d",&n); printf("第一種輸入方式\n"); } printf("第一種輸入方式結(jié)束,限定輸入次數(shù)\n"); while(scanf("%d",&n)==1) { printf("第二種輸入方式\n"); } printf("第二種輸入方式結(jié)束,滿足特定條件\n"); }

TA貢獻(xiàn)10條經(jīng)驗 獲得超5個贊
你需要靈活運用printf()函數(shù),別想太多:
①? int main(){????????????????????????????????????????????????????????② int main(){????????int a,b,c,d;
printf("請在每行輸入一個數(shù)據(jù):\n");????????????????????????????scanf("%d",&a); printf("\n");
printf("First:%d\n",scanf("%d"));???????????????????????????????? scanf("%d",&b); printf("\n");
printf("Second:%d\n",scanf("%d"));????????????????????????????scanf("%d",&c); printf("\n");
printf("Third:%d\n",scanf("%d"));????????????????????????????????scanf("%d",&d); printf("\n");
printf("Fourth:%d\n",scanf("%d"));????????????????????????????printf("a=%d\tb=%d\tc=%d\td=%d\n",a,b,c,d);
return 0;?????????????????????????????????????????????????????????????????????return 0;
}?????????????????????????????????????????????????????????????????????????????????}
建議使用第二種,第一種我也是突發(fā)奇想,不知道可不可以,不過重在嘗試嘛...???????

TA貢獻(xiàn)1017條經(jīng)驗 獲得超1032個贊
如果限定輸入次數(shù)就用for循環(huán),不限定輸入次數(shù)而是有某種特定情況就用while循環(huán)。
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