public class dian{ double x,y,z; dian(double _x,double _y,double _z){ x=_x; y=_y; z=_z; } void setx(double _x){ x=_x; } void sety(double _y){ y=_y; } void setz(double _z){ z=_z; } double juli(dian p){ return (x-p.x)*(x-p.x)+ (y-p.y)*(y-p.y)+ (z-p.z)*(z-p.z); } public static void main(String[] args){ dian k=new dian(1.3,2.3,3.3); dian k2=new dian(1.0,2.0,3.0); System.out.println(k.juli(k2));}}對(duì)于double juli(dian p){ return (x-p.x)*(x-p.x)+ (y-p.y)*(y-p.y)+ (z-p.z)*(z-p.z); }括號(hào)里面你的不太明白 dian P的意思是調(diào)用了上面的dian 的方法么?不太理解為什么能讓第一個(gè)輸入的參數(shù)減去第二個(gè)輸入的參數(shù)
馬士兵老師講的代碼有些不懂
qq_無(wú)此玩家ID_04110506
2016-10-04 17:19:17