package TestPackage;class WaterSource {private String s;WaterSource() {System.out.println("WaterSource()");s = "Constructed";}public String toString() {return s;}public class SprinklerSystem {private String value1,value2,value3,value4;private WaterSource source = new WaterSource();private int i ;private float f;public String toString() {return"value1 = " + value1 + " " + "value2 = " + value2 + " " + "value3 = " + value3 + " " +"value4 = " + value4 + "\n" + "i = " + i + " " + "f = " + f + " " +"Source = " + source;}}public static void main(String[] args) {SprinklerSystem sprinklers = new SprinklerSystem();System.out.println(sprinklers);}}main方法第一句SprinklerSystem sprinklers = new SprinklerSystem(); eclipse報出的錯是No enclosing instance of type WaterSource is accessible. Must qualify the allocation with an enclosing instance of type WaterSource (e.g. x.new A() where x is an instance of WaterSource).請問這是為什么?
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我是偶哦
TA貢獻10條經(jīng)驗 獲得超3個贊
public class SprinklerSystem { -->?public static class SprinklerSystem { ? 這是內(nèi)部類的語法,內(nèi)部靜態(tài)類不需要有指向外部類的引用。但非靜態(tài)內(nèi)部類需要持有對外部類的引用。
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