var?$successTipsContainerLeft=($(window).width()-506)/2+"px"; //獲取窗口可視區(qū)后定位
var?$successTipsContainerTop=($(window).height()-245)/2+"px";
$(".successTipsContainer").css("left","$successTipsContainerLeft");
alert($successTipsContainerTop);???????????????????????????????????????????????????//可以彈出計算后的值,如300px
$(".successTipsContainer").css("top","$successTipsContainerTop");???????????????//$successTipsContainerTop換成300px之類有效果,可是這個沒效果
這幾行js(jquery)代碼為什么不能將彈出提示框定位在窗口中間?
newsudhc3634140
2016-09-02 19:19:28