第七色在线视频,2021少妇久久久久久久久久,亚洲欧洲精品成人久久av18,亚洲国产精品特色大片观看完整版,孙宇晨将参加特朗普的晚宴

為了賬號(hào)安全,請(qǐng)及時(shí)綁定郵箱和手機(jī)立即綁定
已解決430363個(gè)問題,去搜搜看,總會(huì)有你想問的

請(qǐng)問我的代碼有什么問題,題目如下

請(qǐng)問我的代碼有什么問題,題目如下

C++
慕粉3127126 2016-08-23 07:31:50
Common?permutation Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:32768KBTotal submit users: 1060, Accepted users: 951Problem 10048 : No special judgement Problem descriptionGiven two strings of lowercase letters, a and b, print the longest string x of lowercase letters such that there is a permutation of x that is a subsequence of a and there is a permutation of x that is a subsequence of b.InputInput consists of pairs of lines. The first line of a pair contains a and the second contains b. Each string is on a separate line and consists of at most 1,000 lowercase letters. OutputFor each subsequent pair of input lines, output a line containing x. If several x satisfy the criteria above, choose the first one in alphabetical order. Sample Inputpretty women walking down the streetSample Outpute nw etProblem SourceUAL?1999我的代碼如下?#include<iostream>#include<string>?using namespace std;int main(){string a,b;while(cin>>a>>b){int c[26]={0},d[26]={0};int? n1=a.length(),n2=b.length();for(int i=0;i<n1;i++){if(c[(int)a[i]-97]==0){c[(int)a[i]-97]=1;}}for(int i=0;i<n2;i++){if(d[(int)b[i]-97]==0){d[(int)b[i]-97]=1;}}for(int i=0;i<26;i++){if(c[i]!=0&&d[i]!=0)cout<<char(i+97);}cout<<endl;}}
查看完整描述

1 回答

?
JustWannaHugU

TA貢獻(xiàn)452條經(jīng)驗(yàn) 獲得超796個(gè)贊

while(cin>>a>>b)這句別用cin,用gets

查看完整回答
反對(duì) 回復(fù) 2016-08-23
  • 1 回答
  • 1 關(guān)注
  • 1488 瀏覽

添加回答

舉報(bào)

0/150
提交
取消
微信客服

購課補(bǔ)貼
聯(lián)系客服咨詢優(yōu)惠詳情

幫助反饋 APP下載

慕課網(wǎng)APP
您的移動(dòng)學(xué)習(xí)伙伴

公眾號(hào)

掃描二維碼
關(guān)注慕課網(wǎng)微信公眾號(hào)