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function?count(){ ????var?one?=parseInt(document.getElementById("txt1").value)//獲取第一個(gè)輸入框的值 ????var?two=parseInt(document.getElementById("txt2").value)????//獲取第二個(gè)輸入框的值 ????var?three?=?document.getElementById("select").value;????//獲取選擇框的值 ????var?four=?""; ????switch(three)?{ ????????case?'+': ????????????four?=one+two? ????????????break; ????????case?'-': ????????????four=one-two ????????????break; ????????case?'*': ????????????four=one*two? ????????????break; ????????case?'/' ????????????four?=one/two ????????default ????????undefined//獲取通過(guò)下拉框來(lái)選擇的值來(lái)改變加減乘除的運(yùn)算法則 ????} ???document.getElementById("fruit").value?=?four;//設(shè)置結(jié)果輸入框的值? ???? ???}?????? ???} ??</script>? ?</head>? ?<body> ???<input?type='text'?id='txt1'?/>? ???<select?id='select'> <option?value='+'>+</option> <option?value="-">-</option> <option?value="*">*</option> <option?value="/">/</option> ???</select> ???<input?type='text'?id='txt2'?/>? ???<input?type='button'?value='?=?'?onclick="count()"/>?<!--通過(guò)?=?按鈕來(lái)調(diào)用創(chuàng)建的函數(shù),得到結(jié)果-->? ???<input?type='text'?id='fruit'?/>
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?
snowmanJS

TA貢獻(xiàn)89條經(jīng)驗(yàn) 獲得超53個(gè)贊

<!--
????主要問(wèn)題是:有的代碼尾部少結(jié)束符。如:
????1.var?one?=parseInt(document.getElementById("txt1").value)//少一個(gè)分號(hào)
????2.var?two=parseInt(document.getElementById("txt2").value)????//少一個(gè)分號(hào)
????3.four?=one+two?
????4.four=one-two
????5.four=one*two?
????6.case?'/'?//少冒號(hào)
????????????four?=one/two?//少一個(gè)分號(hào)
????7.?default?//少冒號(hào)
?????????undefined//?應(yīng)該為four?="undefined"?;
????8.<script></script>中的代碼最后一個(gè)}應(yīng)該去掉。
????
-->
<!DOCTYPE?html>
<html>
<head>
????<meta?charset="utf-8"?/>
????<script>
????function?count(){
????var?one?=parseInt(document.getElementById("txt1").value);//獲取第一個(gè)輸入框的值
????var?two=parseInt(document.getElementById("txt2").value);????//獲取第二個(gè)輸入框的值
????var?three?=?document.getElementById("select").value;????//獲取選擇框的值
????var?four=?"";
????switch(three)?{
????????case?'+':
????????????four?=one+two;
????????????break;
????????case?'-':
????????????four=one-two;
????????????break;
????????case?'*':
????????????four=one*two;
????????????break;
????????case?'/':
????????????four?=one/two;
????????????break;
????????default:
????????????four="undefined";//獲取通過(guò)下拉框來(lái)選擇的值來(lái)改變加減乘除的運(yùn)算法則
????}
????document.getElementById("fruit").value?=?four;//設(shè)置結(jié)果輸入框的值

????}
????</script>
????</head>
????<body>
????<input?type='text'?id='txt1'?/>
????<select?id='select'>
????????<option?value='+'>+</option>
????????<option?value="-">-</option>
????????<option?value="*">*</option>
????????<option?value="/">/</option>
????</select>
????<input?type='text'?id='txt2'?/>
????<input?type='button'?value='?=?'?onclick="count()"/>?<!--通過(guò)?=?按鈕來(lái)調(diào)用創(chuàng)建的函數(shù),得到結(jié)果-->
????<input?type='text'?id='fruit'?/>
???</body>
?</html>


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1 反對(duì) 回復(fù) 2016-08-07
?
KXFT

TA貢獻(xiàn)113條經(jīng)驗(yàn) 獲得超58個(gè)贊

?case?'/'和default都沒(méi)有冒號(hào)



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反對(duì) 回復(fù) 2016-08-07
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