直接將要跳轉的servlet的url-pattern作為跳轉鏈接就行，假設我有一個servlet如下所示(注意url-pattern)：

import?java.io.IOException;
import?javax.servlet.ServletException;
import?javax.servlet.annotation.WebServlet;
import?javax.servlet.http.HttpServlet;
import?javax.servlet.http.HttpServletRequest;
import?javax.servlet.http.HttpServletResponse;

@WebServlet("/CourseInfoManage")????//注意這里，/CourseInfoManage為servlet的url-pattern
public?class?CourseInfoManage?extends?HttpServlet?{
????public?CourseInfoManage()?{
????????super();
????}

	protected?void?doGet(HttpServletRequest?request,?HttpServletResponse?response)?throws?ServletException,?IOException?
	{
		......
	}

	protected?void?doPost(HttpServletRequest?request,?HttpServletResponse?response)?throws?ServletException,?IOException?{
		doGet(request,?response);
		......
	}

}

在jsp頁面的超鏈接中：

<a?href="CourseInfoManage">課程信息管理</a>

java代碼中：

response.sendRedirect("CourseInfoManage");

當然，有時候可能你的jsp頁面和servlet不在同一目錄下，可能需要用絕對路徑。