#include<stdio.h>
int?fun(int?n)
{
????if(1==n)
????????return?1;
????else?
????????return?n*fun(n-1);
}
void?main()
{
????int?m=10;
????int?sum=0;
????do{
???????sum+=fun(m)
????}while(m--);
????pirntf("%d??",sum);
}

用遞歸實(shí)現(xiàn)吧

這不難自己想 ?先把自己變成計(jì)算機(jī)