window.onload=function(){
var?request=new?XMLHttpRequest();
request.open("GET","http://study.163.com?/webDev/couresByCategory.htm",true);
request.send();
request.onreadystatechange=function(){
if?(request.readyState===4&&request.status===200)?{
var?data=JSON.parse(request.responseText);
document.getElementById("name").innerHTML=data.name;
}else{
alert("發(fā)生錯誤"+request.status);
}
}
}
ajax中status返回結果是0是怎么回事？
oldwan
2016-05-31 17:02:57