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編譯原理的詞法分析程序出問(wèn)題?

編譯原理的詞法分析程序出問(wèn)題?

ShallHurk 2016-05-19 14:08:39
package?第二章; import?java.util.Scanner; public?class?詞法分析1? { public?static?char[]?ch1=?new?char[100]; public?static?char[]?ch=new?char[20]; public?static?int[]?c=new?int[20]; public?static?String[]?b; public?static?String?str; public?static?String?s; public?static?int?count=0; ??String[]str1={"abstract","boolean","break","base","case","catch", ???????"char","class","continue","default","do","double",? ???????"else","extends","false","final","finally","float", ???????"for","if","implements","import","instanceof","int", ???????"interface","long","native","new","null","package", ???????"private","protected","public","return","short",?"static", ???????"super","switch","synchronized","this","throw","throws", ???????"transient","try","true","void",?"volatile","while"}; ??char[]ch2={'+','.','-','*','/','%','$','<','>'}; ??char[]ch3={'=',';',',',':','(',')','[',']','{','}'}; ??char[]ch4={'1','2','3','4','5','6','7','8','9','0'}; ??char[]ch5={'A','B','C','D','E','F','G','H','I','J','K', ?????'L','M','N','O','P','Q','R','S','T','U','V', ?????'W','X','Y','Z','a','b','c','d','e','f','g', ?????'h','i','j','k','l','m','n','o','p','q','r', ?????'s','t','u','v','w','x','y','z','_'}; ??public?static?void?main(String[]?args) ?{ ??System.out.println("請(qǐng)輸入字符串:"); ??Scanner?sc?=?new?Scanner(System.in); ??詞法分析1?strin?=?new?詞法分析1(); ?str?=?sc.nextLine(); ??????b=str.split("?"); ?for(int?p=0;p<b.length;p++){ ?s=b[p]; ?ch1=s.toCharArray(); ?strin.Cstr1(); ??????strin.Cch2(); ??????strin.Cch3(); ??????strin.Cch4(); ?} ?????? ?} ??public??void?Cch2() ??{ for?(int?i?=?0;?i?<?ch1.length;?i++) { ??for?(int?j?=?0;?j?<?ch2.length;j++) ??{ ???if(ch1[i]==ch2[j]) ???{ ??System.out.println(ch1[i]?+?"?"+"ch2?"+"?"+j+"?"+"該字符為運(yùn)算符"+"???"); ???} ??} ????} ??} ?? ??public?void?Cch3() ??{ ??for?(int?m?=?0;?m?<??ch1.length;?m++) ??{ ??for?(int?n?=?0;?n?<?ch3.length;?n++) ??{ ???if(ch1[m]==ch3[n]) ???{ ??System.out.println(ch1[m]?+?"?"+"ch3?"+"?"+n+"?"+"該字符為界符"+" ??"); ???} ??} ??????} ??}? ??public?void?Cch4() ??{ ??for?(int?k?=?0;?k?<?ch1.length;?k++) ??{ ??for?(int?l?=?0;?l?<?10;?l++) ??{ ???if(ch1[k]==ch4[l]) ???{ ??System.out.println(ch1[k]?+?"?"+"ch4"+"?"+l+"?"+"該字符為數(shù)字常量"+"???"); ???} ?????} ??} } ?? ??public?boolean?Nch2() ??{ ??int?r=0; ??for(int?m=0;?m<?ch1.length;?m++) ??{ // ??System.out.println(str.length()); ??for(int?m2=0;?m2<9;?m2++) ??{ ??if(ch1[m]==ch2[m2]) ??{ ??return?false; ??} ??if(ch1[m]!=ch2[m2]) ??{ ??r++; ?? if(r==(?ch1.length)*(ch2.length)) { return?true; } ??} ? ??} ??} return?false;? ??} ?? ??public?boolean?Nch3() ??{ ??int?s=0; ??for(int?n=0;?n<?ch1.length;?n++) ??{ ??for(int?n2=0;?n2<ch3.length;?n2++) ??{ ??if(ch1[n]==ch3[n2]) ??{ ??return?false; ??} ??if(ch1[n]!=ch3[n2]) ??{ ??s++; ??if(s==(?ch1.length)*(ch3.length)) ??{ ??return?true; ??} ??} ?? ??} ??}?return?false; ??} ?? ???public?int?Cstr1() ??{ ??for?(int?k1=?0;?k1?<??b.length;?k1++) ??{ ??for(int?k2=0;k2<str1.length;k2++) ??{ ??if(b[k1].equals(str1[k2])) ??{ ??System.out.println(str1[k2]?+?"?"+"str1"+"?"+k1+"?"+"該單詞為關(guān)鍵字"+"???"); // break; ????return?0; ??} ??} ?? ??} for(int?kk=0;kk<ch5.length;kk++) ?{ //???????????System.out.println(ch5[kk]); ? if(ch1[0]==ch5[kk]&&Nch2()&&Nch3()) ??????{ ? System.out.println(str+"?"+"該單詞為標(biāo)識(shí)符"+"???");?? ????????break; ??} ?????? ?}? ?? ? ??return?0;? ??} ? }各位大神好,上面是我的代碼,出了點(diǎn)問(wèn)題:當(dāng)我輸入表達(dá)式"if a+n=9 then a=0",程序應(yīng)該輸出{if str1 19 該單詞為關(guān)鍵字 ??a ?該單詞為標(biāo)識(shí)符+ ch2 ?0 該字符為運(yùn)算符 ?n ? 該單詞為標(biāo)識(shí)符= ch3 ?0 該字符為界符  ?9 ch4 8 該字符為數(shù)字常量 ??then 該單詞為標(biāo)識(shí)符a ?該單詞為標(biāo)識(shí)符= ch3 ?0 該字符為界符  ?0 ch4 9 該字符為數(shù)字常量},但是,運(yùn)行以后卻輸出這樣的:{if str1 0 該單詞為關(guān)鍵字 ??if str1 0 該單詞為關(guān)鍵字 ??+ ch2 ?0 該字符為運(yùn)算符 ??= ch3 ?0 該字符為界符  ?9 ch4 8 該字符為數(shù)字常量 ??if str1 0 該單詞為關(guān)鍵字 ??if str1 0 該單詞為關(guān)鍵字 ??= ch3 ?0 該字符為界符  ?0 ch4 9 該字符為數(shù)字常量},麻煩大神們幫我看看,謝謝了!? ?
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