LinearLayout.LayoutParams lp = (LinearLayout.LayoutParams) mTabLine.getLayoutParams();lp.leftMargin = (int) (positionOffset * mScreen1_3 + position * mScreen1_3);mTabLine.setLayoutParams(lp);
- 0 回答
- 0 關(guān)注
- 1711 瀏覽
添加回答
舉報
0/150
提交
取消