6 回答

TA貢獻(xiàn)23條經(jīng)驗 獲得超7個贊
????int?i=0; ????int?j=0; String?str="want?you?to?know?one?thing"; for(i=0;i<str.length();i++){ if(str.charAt(i)=='n'){ j++; } } System.out.print(j);

TA貢獻(xiàn)16條經(jīng)驗 獲得超10個贊
String?str?=?"want?you?know?one?thing"; int?num=0; for(int?i=0;?i<str.length();?i++){ if(str.charAt(i)?==?'n'){ num++; } } System.out.println(num);

TA貢獻(xiàn)26條經(jīng)驗 獲得超19個贊
。。。哥們。。。作業(yè)的話自己做一做領(lǐng)悟得更深一些吧。。直接要代碼對自己的學(xué)習(xí)一點也不好。。。你可以多問問細(xì)節(jié)。。

TA貢獻(xiàn)11條經(jīng)驗 獲得超0個贊
String?str?=?"want?you?to?know?one?thing"; int?n?=?'n'; char?[]?chars?=?str.toCharArray(); int?count?=?0; for?(int?i?=?0;i?<?chars.length;i++){ ????if((int)chars[i]?==?n){ ????????count?++; ????} }

TA貢獻(xiàn)114條經(jīng)驗 獲得超93個贊
親測可用
String ss = "want you to know one thing";
?? ??? ?byte[] ssb= ss.getBytes();
?? ??? ?byte[] s = "n".getBytes();
?? ??? ?int i = 0;
?? ??? ?for (byte b : ssb) {
?? ??? ??? ?if(b == s[0]){
?? ??? ??? ??? ?i++;
?? ??? ??? ?}
?? ??? ?}
?? ??? ?System.out.println(i);

TA貢獻(xiàn)30條經(jīng)驗 獲得超6個贊
String s= "want you to know one thing";
String[] ssss = s.split("n");
ssss 的長度-1;
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