@Override
public?boolean?onContextItemSelected(MenuItem?item)?{
???switch?(item.getItemId()){
????????case?101:
????????????Toast.makeText(this,?"我點(diǎn)擊了新建",?Toast.LENGTH_SHORT).show();
????????????break;
????????case?102:
????????????Toast.makeText(this,?"我點(diǎn)擊了復(fù)制",?Toast.LENGTH_SHORT).show();
????????????break;
????????case?103:
????????????Toast.makeText(this,?"我點(diǎn)擊了剪切",?Toast.LENGTH_SHORT).show();
????????????break;
????????case?104:
????????????Toast.makeText(this,?"我點(diǎn)擊了刪除",?Toast.LENGTH_SHORT).show();
????????????break;
????}
????return?super.onContextItemSelected(item);
}

如上，ContextMenu既然是長(zhǎng)按某個(gè)item，那我如何拿到我要操作的那個(gè)Item對(duì)象，或者說(shuō)如何確定ListView的position呢？