求大神解答
public class Demo {
public static void main(String[] args) {
// TODO Auto-generated method stub
String[] str={"abcdaabesase"};
int count=0;
for(int i=0;i<str.length;i++){
if(str[i]=="a"){
count++;
}
}
System.out.println("a字母出現(xiàn)"+count+"次"); //結(jié)果什么是0次啊
}
}
2015-08-05
因為你數(shù)組定義的時候只有一個下標，長度只是1，值是abcdaabesase。
建議把這一行
String[]?str={"abcdaabesase"};改成
String[]?str={"a","b","c","d","a","a","b","e","s","a","s","e"};全代碼
public?class?HelloWorld?{ ????public?static?void?main(String[]?args)?{ //?定義一個字符串 String[]?str={"a","b","c","d","a","a","b","e","s","a","s","e"}; ????????int?count=0; ????????for(int?i=0;i<str.length;i++){ ????????????if(str[i]=="a"){ ????????????count++; ????????????} ????????} ????????System.out.println("a字母出現(xiàn)"+count+"次");?//好厲害哦，4次了耶~~ ????} }2015-08-05
String[] str={"abcdaabesase"};你這樣表示是一個字符串，你可以打印一下System.out.println(str.length);只會顯示1，所以你的字符串是abcdaabesase，并沒有a