輸出效果應(yīng)是這樣“XXXX年XX月X日 星期X--班級(jí)總分為:81” ,誰(shuí)能告訴我哪里錯(cuò)了???多謝!
!DOCTYPE? HTML>
<html >
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>系好安全帶,準(zhǔn)備啟航</title>
<script type="text/javascript">
? //通過(guò)javascript的日期對(duì)象來(lái)得到當(dāng)前的日期,并輸出。
? var mydate=new Date();
? var a=mydate.getFullYear();
? var b=mydate.getMonth();
? var c=mydate.getDate();
? var d=mydate.getDay();
? var weekday=["星期天","星期一"," 星期二"," 星期三","星期四","星期五","星期六"];
?
?
?
? //成績(jī)是一長(zhǎng)竄的字符串不好處理,找規(guī)律后分割放到數(shù)組里更好操作哦
? var scoreStr = "小明:87;小花:81;小紅:97;小天:76;小張:74;小小:94;小西:90;小伍:76;小迪:64;小曼:76";
?? var myarr=new Array();
?? myarr=scoreStr.split(";")
?? var myarr2=new Array();
?? for(var i=0;i<=myarr.length-1;i++){
?????? myarr2[i]=new Array();
?????? myarr2[i]=myarr.split(":");
?? }
? //從數(shù)組中將成績(jī)撮出來(lái),然后求和取整,并輸出。
? var sum=0;
? var ave;
? for(var i=0;i<=myarr.length-1;i++){
????? sum=sum+myarr[i][1];
? }
? ave=sum/myarr.length;
? document.write(a + "年" + b + "月" + c "日 " + weekday[d] + "--班級(jí)總分為:" + ave);
</script>
</head>
<body>
</body>
</html>
2016-07-03
我給你的答案!
<!DOCTYPE? HTML>
<html >
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>系好安全帶,準(zhǔn)備啟航</title>
<script type="text/javascript">
? //通過(guò)javascript的日期對(duì)象來(lái)得到當(dāng)前的日期,并輸出。
?
? var mydate=new Date();
? var a=mydate.getFullYear();
? var b=mydate.getMonth()+1;
? var c=mydate.getDate();
? var d=mydate.getDay();
? var weekday=["星期天","星期一"," 星期二"," 星期三","星期四","星期五","星期六"];
?
?
? //成績(jī)是一長(zhǎng)竄的字符串不好處理,找規(guī)律后分割放到數(shù)組里更好操作哦
? var scoreStr = "小明:87;小花:81;小紅:97;小天:76;小張:74;小小:94;小西:90;小伍:76;小迪:64;小曼:76";
?
??? var sum =new Array();
??? sum = scoreStr.split(";")
??? var s = new Array();
??? for(var i=0;i<sum.length;i++){
??????? s[i]=sum[i].split(":")[1];
??? }
?document.write(a+"年"+b+"月"+c+"日?? "+weekday[d]+
? "--班級(jí)總分為:"+avg(s)+"<br/>");
???
? //從數(shù)組中將成績(jī)撮出來(lái),然后求和取整,并輸出。
? function avg(soc){
????? var sum = 0;
????? var avg = 0;
????? for(var i = 0;i<soc.length;i++){
????????? sum+=parseInt(soc[i])
????? }
????? avg = sum/(soc.length);
??? return avg;
? }
</script>
</head>
<body>
</body>
</html>
2015-07-20
2015-07-20
http://idcbgp.cn/qadetail/87559
看這里的~