#include <stdio.h>
int main()
{
??? int sum, num;? //變量分別接受偶數(shù)與偶數(shù)和
??? sum =0;
??? for(num = 0;? num<=10 ;? num++?? ) ;//for循環(huán)條件與num的變化值
??? {
???????? sum+=num ;?? //計算每次偶數(shù)相加的和sum
??? }
??? printf("10以內(nèi)數(shù)的和為：%d", sum);
??? return 0;
}