這樣可以么?
#?coding=utf-8 s1?=?set([1,?2,?3,?4,?5]) s2?=?set([1,?2,?3,?4,?5,?6,?7,?8,?9]) if?not?s1.isdisjoint(s2): ????if?s1.issubset(s2): ????????for?num?in?s1: ????????????print(num) ????else: ????????for?number?in?s2: ????????????print(number) else: ????print('無重合')
2023-02-10
我運(yùn)行了一下,沒啥大問題,最后的輸出報(bào)錯(cuò)了,改成none就沒問題了,能正常運(yùn)行
2023-01-14
,,,