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為什么1<=i<=100,有前面的<=就提交不了了啊,求解答,謝謝

#include <stdio.h>

int main()

{

? ? int i,sum=0;

? ? i=1;

? ? while(? ?1<=i<=100? )? //循環(huán)條件應(yīng)該是什么呢?

? ? {

? ? ? ? sum=sum+i;

? ? ? ? ?i++;? ? ? ? ?//這里是不是應(yīng)該改變循環(huán)變量的值

? ? }

? ? printf("100以內(nèi)所有整數(shù)之和為:%d\n", sum);

? ? return 0;

}


正在回答

2 回答

這里要用1<=i&&i<=100

0 回復(fù) 有任何疑惑可以回復(fù)我~
#1

qq_慕九州4327935 提問者

對(duì)哦,謝謝!
2021-10-23 回復(fù) 有任何疑惑可以回復(fù)我~


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為什么1<=i<=100,有前面的<=就提交不了了啊,求解答,謝謝

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