cout使用如何16進制輸出
#include<stdio.h>
#include<iostream>
int?main(int?argc,char?**argv)
{
????int?a[5];
????std::cout<<"a[1]:"<<a[1]<<"\na[2]:"<<a[2]<<"\na[3]:"<<a[3]<<"\na[4]:"<<a[4]<<std::endl;
????return?0;
}這樣輸出全是0，請問如何16進制輸出？
慕虎3145518
2021-08-23
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2021-08-23
改為std::cout<<"a[1]:"<<&a[1]<<"\na[2]:"<<&a[2]<<"\na[3]:"<<&a[3]<<"\na[4]:"<<&a[4]<<std::endl;