為什么這個(gè)會(huì)報(bào)錯(cuò)呢？
# Enter a code
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
print s1.isdisjoint(s2)
s3 = set([0,])
for i in s1:
? ? if i in s2:
? ? ? ? s3.add[i]
print 'The overlapping elements are', s3
棹孤舟
2021-08-15
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2021-08-16
print(s1.isdisjoint(s2))
不是?
print s1.isdisjoint(s2)
2021-08-20
這里明明是在s3.add[i]這里出出問(wèn)題了。add是方法用的是(),應(yīng)該是s3.add(i);