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'為什么i++放在sum上面就變成5150

#include <stdio.h>

int main()

{

? ? int i,sum=0;

? ? i=1;

? ? while(? ?i<=100? )? //循環(huán)條件應該是什么呢？

? ? {

? ? ? ? i++;

? ? ? ? sum=sum+i;

??

? ? ? ? ? ? ? ? ?//這里是不是應該改變循環(huán)變量的值

? ? }

? ? printf("100以內所有整數(shù)之和為：%d\n", sum);

? ? return 0;

}

weixin_慕俠2446508

2021-08-07

源自：C語言入門 4-6

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weixin_慕前端3492105
2021-08-07

你把i++放在sum上面之后，程序是這樣運行的：

（第一次）：i++就是i+1=2? ?然后i=2代入sum=sum+i中，即sum=0+2

（第二次）：i++就是i+1=3? ?然后i=3代入sum=sum+i中，即sum=2+3

但是實際上程序是這樣運行才對的

（第一次）：i=1先代入sum=sum+i中，即sum=0+1，然后i++即i=2

（第二次）：i=2先代入sum=sum+i中，即sum=1+2，然后i++即i=3.

這里是一個循環(huán)體，也就是說循環(huán)100次，每次都比正確的多加了數(shù)

2 回復有任何疑惑可以回復我~

#1

weixin_慕前端3492105

同時這里要注意一點就是： i++; 這一句單獨成一行的時候，表示i最后+1了，但是未+1之前的i是沒有用到的，因為;號就表示這一行已經(jīng)結束了，只有這一行得到的結果i+1才能用到下一行去。因此在如果把i++放在sum前面，這樣sum=0+2了，因為此時的i已+1了，上一行的i++；未代入的i=1因為上一行已經(jīng)結束，所以就不能用了。如果要i=1能用，那就要在;號之前，也就是語句結束之前加一個i的表達式如：printf("%d\n",i++),這個時候就是i先代入表達式，然后i再+1了

2021-08-07 回復有任何疑惑可以回復我~

#2

weixin_慕俠2446508 提問者

那題目變成 ++i; sum=sum+i; 那第一次運行是什么樣的 i++和++i在這里體現(xiàn)不出區(qū)別嗎

2021-08-07 回復有任何疑惑可以回復我~

#3

weixin_慕前端3492105 回復 weixin_慕俠2446508 提問者

體現(xiàn)不出來，++i和i++如果單獨成一行的話，實際上得出的結果是一樣的，那就是i=i+1，其他因為分號;的原因，表示語句已經(jīng)結束，未+1之前的i不能作用于上一行或者下一行，所以可以說單獨成一行的話，++i和i++是一樣的

2021-08-08 回復有任何疑惑可以回復我~

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