這個只能手動排序嗎 那如果人數(shù)很多要怎么操作
問題描述:
有主動排序的方法嗎
阿差
2021-07-31
4 回答
舉報
0/150
提交
取消
2023-04-23
students = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']?
score = [89, 72, 88, 79, 99]
sort = sorted(zip(students,score),key=lambda x: x[1],reverse=True)
print(sort)
print(zip(*sort)[0])
2022-01-05
自己寫代碼:
結果：
代碼:
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
scores = [89, 72, 88, 79, 99]
for i in range(len(scores)):
? ? s = scores[i]
? ? flag = i
? ? for j in range(i,len(scores)):
? ? ? ? if(scores[flag] < scores[j]):
? ? ? ? ? ? flag = j
? ? temp = ''
? ? x = 0
? ? temp = names[i]
? ? names[i] = names[flag]
? ? names[flag] = temp
? ? x = scores[i]
? ? scores[i] = scores[flag]
? ? scores[flag] = x
print(scores)? ?
print(names)
2021-08-02
# Enter a code
def get_second(elem):
? ? return elem[1]
L = [('Alice',89), ('Bob',72), ('Candy',88), ('David',79), ('Ellena',99)]
L.sort(key=get_second,reverse=True)
print(L)
2021-08-02
# Enter a code
def get_second(elem):
? ? return elem[1]
L = [('Alice',89), ('Bob',72), ('Candy',88), ('David',79), ('Ellena',99)]
L.sort(key=get_second,reverse=True)
print(L)