為什么會(huì)運(yùn)行失敗
#include <stdio.h>
int main()
{
??? /* 定義需要計(jì)算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? int i,sum;
??? /*
???? * 請(qǐng)使用switch語句，if...else語句完成本題
???? * 如有想看小編思路的，可以點(diǎn)擊左側(cè)任務(wù)中的“不會(huì)了怎么辦”
???? * 小編還是希望大家獨(dú)立完成哦~
???? */
??? switch(month)
??? {
??????? case 1:sum=0;break;
??????? case 2:sum=31;break;
??????? case 3:sum=31+29;break;
??????? case 4:sum=31+29+31;break;
??????? case 5:sum=31+29+31+30;break;
??????? case 6:sum=31+29+31+30+31;break;
??????? case 7:sum=31+29+31+30+31+30;break;
??????? case 8:sum=31+29+31+30+31+30+31;break;
??????? case 9:sum=31+29+31+30+31+30+31+31;break;
??????? case 10:sum=31+29+31+30+31+30+31+31+30;break;
??????? case 11:sum=31+29+31+30+31+30+31+31+30+31;break;
??????? case 12:sum=31+29+31+30+31+30+31+31+30+31+30;break;
??????? default:printf("一年12個(gè)月")；break;
??? }
???
??? sum=sum+day;
??? if(year%400==0)
??? i=1;
??? else
??? i=0;
??? if(i==0&&month>2)
??? sum--;
??? printf("%d年%月%日是該年的第%d天"，year,month,day,sum)；
????
????
???
?return 0;
}
2020-08-16
#include?<stdio.h>int?main()?{?????int?year?=?2008;????int?month?=?8;????int?day?=?8;????int?i,j;????if(year%100==0&&year%400==0||year%4==0&&year%100!=0)i=1;????else?i=0;????switch(month)????{????????case?1:j=day;break;????????case?2:j=31+?day;break;????????case?3:j=31+?28+?day;break;????????case?4:j=31+?28+?31+?day;break;????????case?5:j=31+?28+?31+?30+?day;break;????????case?6:j=31+?28+?31+?30+?31+?day;break;????????case?7:j=31+?28+?31+?30+?31+?30+?day;break;????????case?8:j=31+?28+?31+?30+?31+?30+?31+day;break;????????case?9:j=31+?28+?31+?30+?31+?30+?31+?31+?day;break;????????case?10:j=31+?28+?31+?30+?31+?30+?31+?31+?30+day;break;????????case?11:j=31+?28+?31+?30+?31+?30+?31+?31+?30+?31+day;break;????????case?12:j=31+?28+?31+?30+?31+?30+?31+?31+?30+?31+?30+?day;break;????}????if(i==1)j+=1;????printf("%d年%d月%d日是該年的第%d天",year,month,day,j);????return?0;}2020-08-13
#include <stdio.h>
int main()?
{?
? ? int year = 2008;
? ? int month = 8;
? ? int day = 8;
? ? int i,j;
? ? if(year%100==0&&year%400==0||year%4==0&&year%100!=0)i=1;
? ? else i=0;
? ? switch(month)
? ? {
? ? ? ? case 1:j=day;break;
? ? ? ? case 2:j=31+ day;break;
? ? ? ? case 3:j=31+ 28+ day;break;
? ? ? ? case 4:j=31+ 28+ 31+ day;break;
? ? ? ? case 5:j=31+ 28+ 31+ 30+ day;break;
? ? ? ? case 6:j=31+ 28+ 31+ 30+ 31+ day;break;
? ? ? ? case 7:j=31+ 28+ 31+ 30+ 31+ 30+ day;break;
? ? ? ? case 8:j=31+ 28+ 31+ 30+ 31+ 30+ 31+day;break;
? ? ? ? case 9:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ day;break;
? ? ? ? case 10:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+day;break;
? ? ? ? case 11:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+ 31+day;break;
? ? ? ? case 12:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+ 31+ 30+ day;break;
? ? }
? ? if(i==1)j+=1;
? ? printf("%d年%d月%d日是該年的第%d天",year,month,day,j);
? ? return 0;
}