設(shè)計思路應(yīng)該沒有問題呀,為什么總顯示輸出錯誤?
#include <stdio.h>
int main()
{?
??? int year = 2008;
??? int month = 8;
??? int day = 8;
? ? int numbers;
?if(year%4==0 && year%100!=0 || year%400==0)
?{
??switch(month)
??????? {
??????? ?case 1:
??????? ?case 2:
??????? ???? numbers = (month-1)*31 + day;
??????? ???? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
??????? ?case 3:
??????? ?case 4:
??????? ?case 5:
??????? ?case 6:
??????? ?case 7:
??????? ?case 8:
??????? ???? numbers = (month/2)*31 + ((month-3)/2)*30 + 29 + day;
??????? ???? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
??????????? default:
??????????????? numbers = ((month+1)/2)*31 + ((month-4)/2)*30 + 29 + day;
??????????????? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
??}
?}
?else
?{
??switch(month)
??????? {
??????? ?case 1:
??????? ?case 2:
??????? ???? numbers = (month-1)*31 + day;
??????? ???? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
??????? ?case 3:
??????? ?case 4:
??????? ?case 5:
??????? ?case 6:
??????? ?case 7:
??????? ?case 8:
??????? ???? numbers = (month/2)*31 + ((month-3)/2)*30 + 28 + day;
??????? ???? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
??????????? default:
??????????????? numbers = ((month+1)/2)*31 + ((month-4)/2)*30 + 28 + day;
??????????????? printf("該日期對應(yīng)該年的%d天",numbers);
??????? ???? break;
???? }
??? }
?return 0;
}
2020-06-02
”輸出錯誤“只是因為你的printf里面的輸出和小編規(guī)定的不一樣,因此而已。運行成功了就可以了。