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無法返回“添加錯(cuò)誤的提示”

添加成功的例子過了，但是添加錯(cuò)誤的時(shí)候而比如不輸入年齡就直接會(huì)報(bào)錯(cuò)，而不是返回頁面，

<!--?成功提示框?-->
@if(Session::has('success'))
<div?class="alert?alert-success?alert-dismissible">
????<button?type="buttn"?class="close"?data-dismiss="alert"?aria-label="Close"><span?aria-hidden="true">&times;</span>
????</button>
????<strong>成功！</strong>{{session::get('success')}}<!--?操作成功提示?-->??????</div>
@endif
<!--?失敗提示框?-->
@if(Session::has('error'))
<div?class="alert?alert-danger?alert-dismissible">
????<button?type="buttn"?class="close"?data-dismiss="alert"?aria-label="Close"><span?aria-hidden="true">&times;</span>
????</button>
????<strong>失??！</strong><!--?操作失敗提示?-->?{{session::get('error')}}?????</div>
@endif

public?function?save(Request?$request){
????$data=$request->input('student');
????$student=new?Studentm();
????$student->name=$data['name'];
????$student->age=$data['age'];
????$student->sex=$data['sex'];
????if(!$student->save()){
????????return?redirect('Student/index')->with('success','添加成功');
????}else{
????????redirect()->back();
????}
????return?view('student.create');
}

東堂

2020-03-22

源自：輕松學(xué)會(huì)Laravel-表單篇 2-4

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1 回答

qq_藍(lán)色依戀_0
2020-04-03

沒有添加驗(yàn)證 ?需要在添加之前加入驗(yàn)證?

$validator=\Validator::make($request->input(),[
????'student.name'=>'required|min:2|max:10',
????'student.age'=>'required|integer',
????'student.sex'=>'required|integer'
],[
????'required'=>":attribute不能為空",
????'integer'=>":attribute必須是整數(shù)",
????'min'=>':attribute最小不能少于2字符'
],[
????'student.name'=>'姓名',
????'student.age'=>'年齡',
????'student.sex'=>'性別'
]);
if($validator->fails()){
????return?redirect()->back()->withErrors($validator)->withInput();
}