def?average(*args):
????sum?=?0.0
????if?len(args)?==?0:
????????return?sum
????for?x?in?args:
????????sum?=?sum?+?x
????return?sum?/?len(args)
print?average()
print?average(1,?2)
print?average(1,?2,?2,?3,?4)

#請(qǐng)問(wèn)為什么這里面的x遍歷出來(lái)后直接是args值的和呢？

如果args為（1,2,3,4），遍歷出來(lái)也應(yīng)該是1,2,3,4啊？