這么寫為什么不行啊
#include <stdio.h>
int main()
{
??? /* 定義需要計算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? int sum =0;
??? int er =0;
???
??? switch(month)
??? {
??????? if(year%4==0&&year%400==0)
??????? {
?????????? er=29;
??????????
??????? }else
?????????? er=28;
??????? case 1:
??????????? sum +=day;
??????? case 2:
??????????? sum +=day+31;
??????? case 3:
??????????? sum +=day+er+31;
??????? case 4:
??????????? sum +=day+er+31+31;
??????? case 5:
??????????? sum +=day+er+31+31+30;
??????? case 6:
??????????? sum +=day+er+31+31+30+31;
??????? case 7:
??????????? sum +=day+er+31+31+30+31+30;
??????? case 8:
??????????? sum +=day+er+31+31+30+31+30+31;
??????? case 9:
??????????? sum +=day+er+31+31+30+31+30+31+30;
??????? case 10:
??????????? sum +=day+er+31+31+30+31+30+31+30+31;
??????? case 11:
??????????? sum +=day+er+31+31+30+31+30+31+30+31+30;
??????? case 12:
??????????? sum +=day+er+31+31+30+31+30+31+30+31+30+31;???
??????????? printf("在計算潤年的時候，%d月是%d天",month,sum);
????????????
??? }
?return 0;
}
2019-06-02
#include <stdio.h>
int main()?
{?
? ? /* 定義需要計算的日期 */
? ? int year = 2008;
? ? int month = 8;
? ? int day = 8;
? ? int sum =0;
? ? /*
? ? ?* 請使用switch語句，if...else語句完成本題
? ? ?* 如有想看小編思路的，可以點(diǎn)擊左側(cè)任務(wù)中的“不會了怎么辦”
? ? ?* 小編還是希望大家獨(dú)立完成哦~
? ? ?*/
? ? for(int i=1;i<=month;i++){
? ? ? ? if(i == month){
? ? ? ? ? ? sum += day;
? ? ? ? }else
? ? ? ? if(i == 1 || i ==3 || i ==5|| i ==7 || i ==8 || i ==10 || i ==12){
? ? ? ? ? ? sum+=31;
? ? ? ? }else if(year%4==0 && i==2? ){
? ? ? ? ? ? sum+=29;
? ? ? ? }else if(year%4!=0 && i==2 ){
? ? ? ? ? ? sum += 28;
? ? ? ? }else{
? ? ? ? ? ? sum += 30;
? ? ? ? }
? ? }
? ??
? ? printf("%d年%d月%d日是該年的第%d天",year,month,day,sum);
return 0;
}
2019-06-02
兄弟 這樣寫不累嗎。。。。。