#include<iostream>
#include<string>
using namespace std;

class Teacher{
?? ?public:
?? ??? ?Teacher(string m_strName = "Jim",int age = 1);
?? ??? ?void setName(string name);
?? ??? ?string getName();
?? ??? ?void setAge(int age);
?? ??? ?int getAge();
?? ?private:
?? ??? ?string m_strName;
?? ??? ?int m_iAge;
};

Teacher::Teacher(string name,int age):m_strName("anllla"),m_iAge(age)
{
?? ?cout << "the function is executed!" << endl;
}
void Teacher::setName(string name)
{
?? ?m_strName = name;
}
string Teacher::getName()
{
?? ?return m_strName;
}
void Teacher::setAge(int age)
{
?? ?m_iAge = age;
}
int Teacher::getAge()
{
?? ?return m_iAge;
}

int main()
{
?? ?Teacher t1;
?? ?
?? ?cout << t1.getName() << "," << t1.getAge() << endl;
?? ?
?? ?cout<<"after modifying:" << endl;
?? ?t1.setName("Lily");
?? ?t1.setAge(2);
?? ?
?? ?cout << t1.getName() << "," << t1.getAge() << endl;
?? ?
?? ?return 0;
}

老師，我為了驗(yàn)證初始化列表是先于構(gòu)造函數(shù)執(zhí)行的，在初始化列表中又給了一個(gè)m_strName一個(gè)“anllla”的名字，但是第一次輸出的結(jié)果還是“anlla”

我的疑問是，當(dāng)用初始化列表初始化了一個(gè)“anlla”之后，之后不是接著執(zhí)行構(gòu)造函數(shù)嗎？而構(gòu)造函數(shù)中默認(rèn)賦值是“Jim”，所以第一次輸出m_str_Name時(shí)不應(yīng)該輸出后來覆蓋的那個(gè)“Jim”嗎？